Answer:
The solution of the system is the point (-2,4)
Step-by-step explanation:
we have
[tex]2x-\frac{3}{4}y=-7[/tex] ---> equation A
[tex]x+\frac{1}{2}y=0[/tex] ----> equation B
Solve the system by elimination
Multiply the equation B by -2 both sides
[tex]-2(x+\frac{1}{2}y)=-2(0)[/tex]
[tex]-2x-y=0[/tex] ----> equation C
Adds equation A and equation C
[tex]2x-\frac{3}{4}y=-7\\-2x-y=0\\--------\\\\-\frac{3}{4}y-y=-7\\\\-\frac{7}{4}y=-7\\\\y=4[/tex]
Find the value of x
substitute the value of y in any equation
[tex]x+\frac{1}{2}(4)=0[/tex]
[tex]x+2=0[/tex]
[tex]x=-2[/tex]
The solution of the system is the point (-2,4)
