Answer: Option 'c' is correct.
Step-by-step explanation:
Since we have given that
n = 1200
x = 32% of 1200
So, [tex]\hat{p}=32\5=0.32[/tex]
We need to find 95% confidence interval.
so, z = 1.96
So, margin of error would be
[tex]z\times \sqrt{\dfrac{p(1-p)}{n}}\\\\=1.96\times \sqrt{\dfrac{0.32\times 0.68}{1200}}\\\\=1.96\times 0.0135=[/tex]
So, Interval would be
[tex]\hat{p}\pm \text{margin of error}}\\\\=0.32\pm 0.0263\\\\=(0.32-0.0263,0.32+0.0263)\\\\=(0.2937,0.3463)\\\\=(0.294,0.346)\\\\=(29.4\%,34.6\%)[/tex]
Hence, Option 'c' is correct.