contestada

A cylindrical blood vessel is partially blocked by the buildup of plaque. At one point, the plaque decreases the diameter of the vessel by 69.0 %. The blood approaching the blocked portion has speed v 0 . Just as the blood enters the blocked portion of the vessel, what is its speed v , expressed as a multiple of v 0

Respuesta :

Answer:10.4 times of initial velocity

Explanation:

Given

Diameter reduced by 69 %

it approaches with velocity [tex]v_0[/tex]

suppose its velocity is v during blocked passage

suppose d is the initial diameter and [tex]d_2[/tex] diameter is

[tex]d_2=d(1-0.69)[/tex]

[tex]d_2=0.31 d[/tex]

[tex]A_2=\frac{\pi d_2^2}{4}[/tex]

As flow is constant

[tex]Q_1=Q_2[/tex]

[tex]d^2v_0=d_2^2v[/tex]

[tex]v=10.40 v_0[/tex]