jg235214
contestada

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not
replaced. Let event B be choosing a black ball first and event R be choosing a red ball second.
What are the following probabilities?
P(B) =
P(RIB) =
P(BNR)=
The probability that the first ball chosen is black and the second ball chosen is red is about percent.​

Respuesta :

waqaskhan15836

Answer:

the   probabilities will be following

P(B) =   8/12

P(RIB) =  4/11

P(BNR)=  8/33

probability that the first ball chosen is black and the second ball chosen is red is about  = 24 %

Answer:

(1) 8/12  (2) 4/11 (3) 8/33 (4) 24%

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