He saved $3.30 in all.
Step-by-step explanation:
Let,
Number of nickels = x
Number of dimes = y
According to given statement;
Jeff saved 33 more nickels than dimes.
x = y+33 Eqn 1
He had 4 times as many nickels as dimes.
x = 4y Eqn 2
Putting value of x from Eqn 2 in Eqn 1
[tex]4y=y+33\\4y-y=33\\3y=33[/tex]
Dividing both sides by 3
[tex]\frac{3y}{3}=\frac{33}{3}\\y=11[/tex]
Putting y=11 in Eqn 2
[tex]x=4(11)\\x=44[/tex]
Therefore,
Total coins = 44 nickels + 11 dimes
We know that;
1 nickel = 5 cents
1 dime = 10 cents
Total coins worth = 44*5 + 11*10 = 220+110 = 330 cents
Dividing by 100 to convert into dollars
[tex]\frac{330}{100} = \$3.30[/tex]
He saved $3.30 in all.
Keywords: linear equation, addition
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