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A frictionless pendulum is made with a bob of mass 19.7 kg. The bob is held at height = 0.934 meter above the bottom of its trajectory, and then pushed forward with an initial speed of 2.93 m/s. What amount of mechanical energy does the bob have when it reaches the bottom?

96 J

136 J

265 J

180 J

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opudodennis

Answer:

265 J

Explanation:

[tex]Energy=PE+KE=mgh+ 0.5mv^{2}[/tex] where KE is kinetic energy, PE is potential energy, m is the mass of an object, v is the speed, h is the height and g is acceleration due to gravity.

Substituting 19.7 Kg for mass, 0.934 for h, 2.93 for v and 9.81 for g then

[tex]Energy=19.7(9.81*0.934+0.5*2.93^{2})=265.063303\approx 265 J[/tex]

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