Answer:
equation of circle is (x+5)^2+(y-3)^2=16
Step-by-step explanation:
equation of circle [tex](x-x_1)^2+(y-y_1)^2=r^2
where r=redius of circle,[tex](x_1,y_1)[/tex] is centre of circle
centre of circle=(-5,3)
put the value of centre and redius in the equation
equation of circle [tex]{(x+5)^2+(y-3)^2}[/tex]=4^2