Answer:
V = 3.6127x10⁻²³cm³
mass = 6.009x10⁻²²g
2 atoms
6.022x10²³ atoms in 1 mole
Explanation:
The volume of the unit cell is the lenght to the third power.
V = (3.3058x10⁻¹⁰ m )³ = 3.6127x10⁻²⁹m³× (1x10⁶cm / 1m) = 3.6127x10⁻²³cm³
Using density, mass of a talantalum unit cell is:
3.6127x10⁻²³cm³×(16.634g/cm³)= 6.009x10⁻²²g
As the unit cell is body-centered cube, atoms in an unit cell are:
2 atoms per 6.009x10⁻²²g, 180,9479g (1 mole) contains:
180,9479g × (2atoms / 6.009x10⁻²²g) = 6.022x10²³ atoms in 1 mole
I hope it helps!
