The gravitational force of attraction between two students sitting at their desks in physics class is 3.20 x 10-18 N. If one student has a mass of 50.0 kg and the other has a mass of 60.0 kg, how far apart are the students sitting?

Respuesta :

Answer:

r  =  25*10⁴ m     [please read note]

Step-by-step explanation:

Newton´s law of gravitational force of attraction is:

F  = [ G   m₁ *m₂ ] / r²     (1)

From that equation we know:

G = 6.67 * 10⁻¹¹ [N*m²/kg² ]

F  = 3.20 *10⁻¹⁸ N

Two bodies

 m₁  =  50 kg

 m₂  =  60 kg

question is how far away they are.

By subtitution in equation (1)

3.20*10⁻¹⁸ (N) = {  6.67 * 10⁻¹¹ [N*m²/kg² ] *  50 [kg]*60[ kg] } / r²

3.20*10⁻¹⁸ = 20010 * 10⁻¹¹[  m²] / r²

r²   =  20010/3.20*10⁷ m²

r²   =  6253* 10⁷ m²

r²    =  625,3*10⁸ m²

r  =  25*10⁴ m

Note:

Then I  after looking similar problems in google I conclude there must be an error in problem statement  the result  25*10⁴ is certanly too big for a class room. Maybe F  is 3.20 * 10⁻⁸ then we get  d = 6 mt

The students are 86 m apart from each other.

Newton's law of gravitation states that the force is directly proportional to the product of the two masses and inversely proportional to the square of the distance between them. It is given by:

F = G(m₁m₂)/r²

where m₁ and m₂ are mass, r is the distance, G is constant = 6.67 * 10⁻11 Nm²/kg² and F is the force.

Given m₁ = 50kg, m₂ = 60 kg, F = 3*10⁻¹⁸ N, hence:

3*10⁻¹⁸ N = 6.67 * 10⁻11(50 * 60)/r²

r = 86 m

Hence the students are 86 m apart from each other.

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