Respuesta :
Answer:
The resultant gravitational force is [tex]7.76\times10^{-11}\ N[/tex]
Explanation:
Suppose A coordinate system is constructed on the surface of a pool table, and three objects are placed on the coordinate system as follows: a 1.2 kg object at the origin, a 3 kg object at (0 m,1.8 m), and a 4.6 kg object at (4 m,0 m).
We need to calculate the gravitational force along x axis
Using formula of gravitational
[tex]F_{1}=\dfrac{GmM}{r^2}[/tex]
Where, m = mass of first object
M = mass of object when placed at center
r = distance
G = gravitational constant
Put the value into the formula
[tex]F_{1}=\dfrac{6.672\times10^{-11}\times1.2\times4.6}{(4)^2}[/tex]
[tex]F_{1}=2.301\times10^{-11}\ N[/tex]
We need to calculate the gravitational force along y axis
Using formula of gravitational
[tex]F_{2}=\dfrac{Gm_{1}M}{r^2}[/tex]
Put the value into the formula
[tex]F_{2}=\dfrac{6.672\times10^{-11}\times1.2\times3}{(1.8)^2}[/tex]
[tex]F_{2}=7.413\times10^{-11}\ N[/tex]
We need to calculate the resultant gravitational force
Using formula of resultant gravitational force
[tex]F_{net}=\sqrt{(F_{1}^2+F_{2}^2)}[/tex]
[tex]F_{net}=\sqrt{(2.301\times10^{-11})^2+(7.413\times10^{-11})^2}[/tex]
[tex]F_{net}=7.76\times10^{-11}\ N[/tex]
Hence, The resultant gravitational force is [tex]7.76\times10^{-11}\ N[/tex]
