Calculate the linear acceleration of a car, the 0.200-m radius tires of which have an angular acceleration of 13.0 rad/s2. Assume no slippage and give your answer in m/s2. m/s2 (b) How many revolutions do the tires make in 2.50 s if they start from rest? rev (c) What is their final angular velocity in rad/s? rad/s (d) What is the final velocity of the car in m/s?

Respuesta :

Answer:

linear acceleration = 2.6 m/s²

revolutions = 6.375 rev

final angular velocity = 32.5 rad/s

final velocity = 6.5 m/s

Explanation:

given data

radius r = 0.200 m

angular acceleration =  13.0 rad/s²

time = 2.50 s

to find out

linear acceleration , How many revolutions do the tires , final angular velocity and final velocity

solution

first we get here linear acceleration that is express as

linear acceleration =  angular acceleration × radius   .....................1

linear acceleration =  13 × 0.200

linear acceleration = 2.6 m/s²

and

we get here first final velocity that is

V(f) =  angular acceleration ×  time

V(f) =  13 × 2.5   × [tex]\frac{1rev}{2\pi rad}[/tex]  

V(f) = 5.10 rev/s

and

average velocity = [tex]\frac{V(f)-V(o)}{2}[/tex]    

average velocity = [tex]\frac{5.10- 0}{2}[/tex]  

average velocity = 2.55 rev/s

so revolutions = 2.55  × 2.5

revolutions = 6.375 rev

and

final angular velocity W will be

W = Wo + angular acceleration ×  time

W = 0 + 13 × 2.5 = 32.5

final angular velocity = 32.5 rad/s

and

final velocity will be

final velocity = angular velocity × radius

final velocity = 32.5 × 0.200

final velocity = 6.5 m/s

linear acceleration = 2.6 m/s²

revolutions = 6.375 rev

final angular velocity = 32.5 rad/s

final velocity = 6.5 m/s

What will be the linear acceleration revolutions' final angular velocity and final velocity?

given data

radius r = 0.200 m

angular acceleration =  13.0 rad/s²

time = 2.50 s

to find out

linear acceleration, How many revolutions do the tires , final angular velocity and final velocity

solution

first we get here linear acceleration that is express as

linear acceleration =  angular acceleration × radius   .....................1

linear acceleration =  13 × 0.200

linear acceleration = 2.6 m/s²

and

we get here first final velocity that is

V(f) =  angular acceleration ×  time

[tex]V_{f} =13\times 2.5\times \dfrac{1}{2\pi}[/tex]

V(f) = 5.10 rev/s

and

average velocity = [tex]\frac{V_{f} -V_{0} }{2}[/tex]    

average velocity =[tex]\dfrac{5.10-0}{2}[/tex]  

average velocity = 2.55 rev/s

so revolutions = 2.55  × 2.5

revolutions = 6.375 rev

and

final angular velocity W will be

W = Wo + angular acceleration ×  time

W = 0 + 13 × 2.5 = 32.5

final angular velocity = 32.5 rad/s

and

final velocity will be

final velocity = angular velocity × radius

final velocity = 32.5 × 0.200

final velocity = 6.5 m/s

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