Answer:
The answer to your question is the first option is correct
Step-by-step explanation:
( 8x⁴y⁷) ²/³
[tex]\sqrt[3]{(8x^{4}y^{7})^{2} }[/tex]
[tex]\sqrt[3]{64x^{8} y^{14} }[/tex]
[tex]\sqrt[3]{2^{6} x^{8}y^{14}}[/tex]
2⁶/³x⁶/³y¹²/³[tex]\sqrt[3]{x^{2}y^{2}}[/tex]
2²x²y⁴[tex]\sqrt[3]{x^{2}y^{2}}[/tex]
4x²y⁴[tex]\sqrt[3]{x^{2}y^{2}}[/tex]
