Answer:
Molecular formula of the compound is [tex]C_{2}H_{2}O=C_{10}H_{10}O_{5}[/tex]
Explanation:
Empirical formula of the given compound - [tex]C_{2}H_{2}O[/tex]
Empirical formula mass = [tex](2\times 12g/mol)+(2\times 1g/mol)+(16 g/mol)=42g/mol[/tex]
[tex]\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}[/tex]
[tex]\frac{Molecular\,formula\,mass}{Empirical\,formula\,mass}=\frac{216g/mol}{42g/mol}= 5.15=5[/tex]
[tex]{Molecular\,formula}= 5\times {Empirical\,formula}[/tex]
[tex]= 5\times C_{2}H_{2}O=C_{10}H_{10}O_{5}[/tex]
Therefore, molecular formula of the compound is [tex]C_{2}H_{2}O=C_{10}H_{10}O_{5}[/tex]
