Answer:
Two erythrocytes and 34 E.Coli Bacteria
Explanation:
Given -
Size of human hair i.e width of human hair is equal to [tex]17[/tex] micrometers
Size of an average erythrocytes or red blood cell is equal to 8 micrometers in diameter.
So the number of human erythrocytes could fit across the width of a hair is equal to
[tex]\frac{W_{Hh}}{D_{RBC}}[/tex]
Substituting the given values, we get -
[tex]\frac{17}{8} \\= 2[/tex]
Width of E.Coli bacteria is equal to [tex]0.5[/tex] micrometer
Number of E.Coli bacteria that could fit in with in the human hair is equal to
[tex]\frac{17}{0.5} \\= 34[/tex]
