The standard cell potential (Ecell) for the voltaic cell based on the reaction below is (need answer)_V.

3Sn4+(aq) + 2Cr(s) -----> 2Cr3+(aq) + 3Sn2+(aq)

Use this chart:

Half-reaction | E(V)

Cr3+(aq) + 3e- -----> Cr(s) |-0.74

Fe2+(aq) + 2e- -----> Fe(s) |-0.440

Fe3+(aq) + e- ------> Fe2+(s) |+0.771

Sn4+(aq) +2e- ------> Sn2+(aq) |+0.154

A) -1.02

B) +2.53

C) +1.94

D) -0.59

E) +0.89

The cell potential is the reduction potential of the cathode less than the reduction potential of the anode. In the cathode is happening a reduction, so the compound is gaining electrons. In the anode oxidation is happening, thus the compound is losing electrons.

By the equation:

3Sn⁺⁴(aq) + 2Cr(s) -----> 2Cr⁺³(aq) + 3Sn⁺²(aq)

We see that the oxidation number of Sn is going from +4 to +2, so it's reducing, and the oxidation number of Cr is going from 0 to +3, then it's oxidizing. So,

E°cell = 0.154 - (-0.740)

E°cell = +0.894 V

E°cell ≅ +0.89 V

pstnonsonjoku pstnonsonjoku · Answer 2 · 2022-04-08T13:19:28+02:00

The cell potential of the cell as shown is 0.894 V

What is standard cell potential?

The cell potential is the difference between the electrode potential of the cathode and that of the anode. A positive cell potential shows that a sponteanous reaction is going on.

Now for the reaction; [tex]3Sn4+(aq) + 2Cr(s) ----- > 2Cr3+(aq) + 3Sn2+(aq)[/tex], the cell potential is +0.154 - (-0.74) = 0.894 V

Learn more about cell potential: https://brainly.com/question/11334504