contestada

What is the equation of the line that passes through the point (4,5) and is parallel to the line whose equation is y=2/3x-4

Respuesta :

Answer:

[tex]y=\frac{2}{3}x+\frac{7}{3}[/tex]

Step-by-step explanation:

step 1

Find the slope of the line parallel to the given line

we know that

If two lines are parallel, then their slopes are equal

we have

[tex]y=\frac{2}{3}x-4[/tex] ---> given line

The slope of the given line is [tex]m=\frac{2}{3}[/tex]

so

the slope of the line parallel to the given line is [tex]m=\frac{2}{3}[/tex]

step 2

Find the equation of the line in point slope form

[tex]y-y1=m(x-x1)[/tex]

we have

[tex]m=\frac{2}{3}[/tex]

[tex]point\ (4,5)[/tex]

substitute

[tex]y-5=\frac{2}{3}(x-4)[/tex]

step 3

Convert to slope intercept form

[tex]y=mx+b[/tex]

isolate the variable y

[tex]y-5=\frac{2}{3}x-\frac{8}{3}[/tex]

[tex]y=\frac{2}{3}x-\frac{8}{3}+5[/tex]

[tex]y=\frac{2}{3}x+\frac{7}{3}[/tex]