Answer:
S(t)=[tex]\frac{9t^2}{34}[/tex]
Step-by-step explanation:
We are given that
Th braking distance for a certain car moving at velocity v(in m/s) is given by
[tex]D(v)=\frac{v^2}{34}[/tex]
The velocity of car B(t) t seconds after starting =[tex]B(t)=3t[/tex]
We have to find the value for braking distance S(t) after t seconds.
To find the formula for braking distance we will substitute the value of velocity B(t) in place of v in D(v)
Substitute the value of velocity then we get
Then, we get
The formula for the braking distance S(t) after t seconds=[tex]\frac{(3t)^2}{34}[/tex]
The formula for the braking distance S(t) after t seconds=[tex]\frac{9t^2}{34}[/tex]
