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Using the following thermochemical data, what is the change in enthalpy for the following reaction?


A.

120.9 kJ

B.

-251.1 kJ

C.

251.1 kJ

D.

-120.9 kJ

Using the following thermochemical data what is the change in enthalpy for the following reactionA1209 kJB2511 kJC2511 kJD1209 kJ class=

Respuesta :

Answer:

D. -120.9 kJ

Explanation:

According to Hess's law ,the total enthalpy change for a reaction is the sum of all changes regardless of the stages or the steps of the reaction.

[tex]CaO + 2HCl \rightarrow CaCl_{2} + H_{2}O\ (\Delta H = -186\ kJ)[/tex]....(1)

[tex]CaO + H_{2}O\rightarrow Ca(OH)_{2}\ (\Delta H = - 65 \ kJ)[/tex]

(this reaction should be reversed in order to reach the required reaction )

On reversing the reaction the sign of [tex]\Delta H[/tex] get reversed.

(In this case change sign from '-' to'+'. Hence  [tex]\Delta H[/tex] = + 65 kJ)

[tex]CaO + 2HCl \rightarrow  CaCl_{2} + H_{2}O\ (\Delta H = - 186\ kJ)[/tex]....(1)

[tex]Ca(OH)_{2}   \rightarrow  CaO + H_{2}O\ (\Delta H = + 65 kJ )[/tex]......(2)

Adding equation (1) and (2)

[tex]Ca(OH)_{2} + 2HCl \rightarrow CaCl_{2} + 2H_{2}O[tex]

[tex]Delta H = - 186 + 65 = - 121\kJ[/tex]

[tex]Delta H = - 121\kJ[/tex] (It is nearly equal to -120.9 kJ)