Respuesta :
Answer:
(a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 50 hr is 6.707 m.
Explanation:
Given that,
Energy [tex]Q=300\ m^3/hr[/tex]
Transmissivity [tex]T = 25\ m^2/hr[/tex]
Storage coefficient [tex]S=2.5\times10^{-4}[/tex]
Distance r= 200 m
We need to calculate the draw-down at a distance 200 m from the well after pumping for 50 hr
Using formula of draw-down
[tex]s= \dfrac{Q}{4\pi T}(-0.5772-ln\dfrac{r^2S}{4tT})[/tex]
Put the value into the formula
[tex]s=\dfrac{300}{4\pi\times25}(-0.5772-ln\dfrac{(200)^2\times2.5\times10^{-4}}{4\times25\times50})[/tex]
[tex]s=5.383\ m[/tex]
We need to calculate the draw-down at a distance 200 m from the well after pumping for 200 hr
Using formula of draw-down
[tex]s= \dfrac{Q}{4\pi T}(-0.5772-ln\dfrac{r^2S}{4tT})[/tex]
Put the value into the formula
[tex]s=\dfrac{300}{4\pi\times25}(-0.5772-ln\dfrac{(200)^2\times2.5\times10^{-4}}{4\times25\times200})[/tex]
[tex]s=6.707\ m[/tex]
Hence, (a). The draw-down at a distance 200 m from the well after pumping for 50 hr is 5.383 m.
(b). The draw-down at a distance 200 m from the well after pumping for 200 hr is 6.707 m.
