Answer:
Kc = 0.102
Explanation:
NH₄HS (s) ⇌ NH₃ (g) + H₂S (g)
The equilibrium constant for the above reaction , can be written as the product of the concentration of product raised to the power of stoichiometric coefficients in a balanced equation of dissociation divided by the product of the concentration of reactant raised to the power of stoichiometric coefficients in the balanced equation of dissociation .
Hence ,
Kc = [ NH₃ (g) ][ H₂S (g) ] / [ NH₄HS (s) ]
Since, the state of NH₄HS is solid so, it's concentration will remain constant , hence , the equation can be rearranged as -
Kc = [ NH₃ (g) ][ H₂S (g) ]
From the question ,
[ NH₃ (g) ] = 0.276 M
[ H2S (g) ] = 0.370 M
Now, putting it in the above equation ,
Kc = [ NH₃ (g) ][ H₂S (g) ]
Kc = 0.276 * 0.370
Kc = 0.102
