Respuesta :
Answer: The molarity of a solution made by dissolving 12.6 grams of NaNO3 to make 200 ml of solution is 0.74 M
Explanation:
Molarity is defined as the number of moles of solute dissolved perliter of the solution.
[tex]Molarity=\frac{n\times 1000}{V_s}[/tex]
where,
n= moles of solute
[tex]V_s[/tex] = volume of solution in ml = 1000 ml
[tex]moles of solute =\frac{\text {given mass}}{\text {molar mass}}=\frac{12.6g}{85g/mol}=0.148moles[/tex]
Now put all the given values in the formula of molarity, we get
[tex]Molarity=\frac{0.148moles\times 1000}{200ml}=0.74mole/L[/tex]
Thus the molarity of a solution made by dissolving 12.6 grams of NaNO3 to make 200 ml of solution is 0.74 M
Answer:
The molarity of the solution is 0.740 M
Explanation:
Step 1: data given
Mass of NaNO3 = 12.6 grams
Molar mass of NaNO3 = 84.99 g/mol
Volume = 200 mL = 0.200 L
Step 2: Calculate moles of NaNO3
Moles NaNO3 = mass NaNO3 / molar mass NaNO3
Moles NaNO3 = 12.6 grams / 84.99 g/mol
Moles NaNO3 = 0.148 moles
Step 3: Calculate molarity
Molarity = moles / volume
Molarity = 0.148 moles / 0.200 L
Molarity = 0.740 M
The molarity of the solution is 0.740 M
