If both the radius of the circular trajectory and the speed of the aircraft were reduced by a factor of two, how would the force exerted on the pilot change from the answer you found above ?

Respuesta :

Answer:

halved

Explanation:

radius = r

velocity = v

let the mass is m

Force is centripetal force

F = mv²/r    ... (1)

Now, r' = r/2 and v' = v/2 So,

F' = m v² x 2 / 4 x r

F' = mv²/2r

F' = F/2      (from equation (1)

Thus, the force is halved.

Answer:

Explanation:

Considering aircraft of mass m is moving with constant  velocity v in a trajectory of radius r then the force acting on the body is centripetal force.

Centripetal force will acts on a body when a particle moves in a circular trajectory

It is given by

[tex]F_c=\frac{mv^2}{r}[/tex]

if both  speed and radius is reduced to half then force become

[tex]F'_c=\frac{m\times (0.5v)^2}{0.5r}[/tex]

[tex]F'_c=0.5\cdot \frac{mv^2}{r}[/tex]

Force will reduced to half