Answer:
1.28
Step-by-step explanation:
Given that a sample of 1500 computer chips revealed that 55% of the chips do not fail in the first 1000 hours of their use. The company's promotional literature states that 53% of the chips do not fail in the first 1000 hours of their use.
[tex]H_0: p = 0.53\\\\H_a: p \neq 0.53[/tex]
(Two tailed test for testing sample proportion with population proportion)
Std error of proportion assuming p = 0.53 is
[tex]\sqrt{0.53*0.47/1000} \\=0.0157[/tex]
p difference = 0.02
Z= test statistic = p diff/std error = 1.2775~1.28
