The force exerted on the bottle is 532 N
Explanation:
When the air is removed from inside the bottle, vacuum is created, therefore the external pressure (the atmospheric pressure) is no longer balanced, and it creates a net force downward on the can.
The pressure is related to the force by the equation:
[tex]p=\frac{F}{A}[/tex]
where
p is the pressure
F is the force
A is the area of the can
Here we have:
[tex]p=1.01\cdot 10^5 Pa[/tex] is the atmospheric pressure
r = 0.0410 m is the radius of the can, so the area is
[tex]A=\pi r^2 = \pi (0.0410)^2=5.27\cdot 10^{-3}m^2[/tex]
And solving for F, we can find the force on the can:
[tex]F=pA=(1.01\cdot 10^5)(5.27\cdot 10^{-3})=532 N[/tex]
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