3. A 3.0 × 10−3 kg copper penny drops a distance of 50.0 m to the ground. If 65 percent of the initial potential energy goes into increasing the internal energy of the penny, determine the magnitude of that increase.

Respuesta :

Answer:

The magnitude of the increase is 0.9555J

Explanation:

Potential Energy (PE) = mgh

mass (m) = 3×10^-3kg, acceleration due to gravity (g) = 9.8m/s^2, distance (h) = 50m

PE = 3×10^-3 × 9.8 × 50 = 1.47J

Increase in internal energy = 65% of 1.47J = 0.65 × 1.47J = 0.9555J