Answer:
( [tex]\frac{10}{3}[/tex], - 3 )
Step-by-step explanation:
Given the 2 equations
6x - y = 23 → (1)
3y + 6x = 11 → (2)
Subtracting (2) from (1) term by term eliminates the term in x
(6x - 6x) + (- y - 3y) = (23 - 11), that is
- 4y = 12 ( divide both sides by - 4 )
y = - 3
Substitute y = - 3 into either of the 2 equations and solve for x
Substituting in (1)
6x - (- 3) = 23
6x + 3 = 23 ( subtract 3 from both sides )
6x = 20 ( divide both sides by 20 )
x = [tex]\frac{20}{6}[/tex] = [tex]\frac{10}{3}[/tex]
Solution is ( [tex]\frac{10}{3}[/tex], - 3 )
