See the graph below
Explanation:
Hello, remember to write complete questions in order to get good and exact answers. Here you haven't provided any options, so I could help you in a general way.
We know the following facts:
- The parabola that opens up.
- It has a vertex at (-4,5)
The vertex-form of the equation of a parabola is given by:
[tex]f(x)=a(x-h)^2+k \\ \\ \\ Where: \\ \\ a:Leading \ coefficient \\ \\ \\ (h,k):Vertex[/tex]
In order for the parabola to open up [tex]a[/tex] must be greater than 0, so setting [tex]a=1[/tex] and [tex](h,k)=(-4,5)[/tex] then our equation becomes:
[tex]f(x)=(x-(-4))^2+5 \\ \\ \boxed{f(x)=(x+4)^2+5}[/tex]
Finally, by using graphing tools we get the graph shown below. As you can see the parabola opens up and has its vertex at [tex](-4,5)[/tex]
Learn more:
Zeroes of a parabola: https://brainly.com/question/1469367
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