Respuesta :

Answer:

sec Θ = [tex]\frac{\sqrt{65} }{7}[/tex]

Step-by-step explanation:

Using the trigonometric identity

sec²Θ = tan²Θ + 1

Since 270° < Θ < 360° ← that is fourth quadrant, then

sec Θ > 0, thus

sec²Θ = (- [tex]\frac{4}{7}[/tex])² + 1 = [tex]\frac{16}{49}[/tex] + 1 = [tex]\frac{65}{49}[/tex], then

sec Θ = [tex]\sqrt{\frac{65}{49} }[/tex] = [tex]\frac{\sqrt{65} }{7}[/tex]

claikyn

Answer: sqrt 65/7

Step-by-step explanation:

I take it you meant θ angle, anyway.

we know the tan(θ) = -4/7... alrite, we also know that 270° < θ < 360°, which is another to say that θ is in the IV quadrant, where the adjacent side or "x" value is positive whilst the opposite side or "y" value is negative.

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