Answer:
option C is correct = 25,080 j
Explanation:
Data Given:
mass of water = 200 g
initial temperature = 10 °C
Final temperature = 40 °C
Amount of Heat = ?
Solution:
Formula used to calculate the amount of heat
Q = c.m.ΔT . . . . . (1)
Where:
Q = amount of heat
c = specific heat of water = 4.18 J/g°C
m = mass
ΔT = (t2 - t1) = Change in temperature
First we have to find ΔT
ΔT = (t2 - t1)
ΔT = (40 °C - 10°C )
ΔT = 30 °C
Put values in above equation 1
Q = 4.18 J/g°C x 200 g x 30 °C
Q = 25080 j
So option C is correct
