Respuesta :
Answer:
0.12 mg
Explanation:
Data Given:
no. of molecules of Sucrose (C₁₂H₂₂O₁₁) = 1.2×10¹⁷
mass in mg = ?
Solution:
First we have to find no. of mole
Formula used
no. of mole = no. of molecules / Avogadro's number
Where
Avogadro's number = 6.022 x 10²³
Put values in above formula
no. of mole = 1.2×10¹⁷ / 6.022 x 10²³
no. of mole = 3.5×10⁻⁷
Now we have to find mass of sucrose
For this formula will use
mass in grams = no. of moles x Molar mass . . . . . .(1)
Formula of Sucrose = C₁₂H₂₂O₁₁
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 12(12) +22(1) +11(16)
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 144 +22 + 176
Molar mass of C₁₂H₂₂O₁₁ (Sucrose) = 342 g/mol
put values in equation 1
mass in grams = 3.5×10⁻⁷ x 342 g/mol
mass in grams = 1.2 x 10⁻⁴ g
Convert g to mg
1 g = 1000 mg
1.2 x 10⁻⁴ g = 1.2 x 10⁻⁴ x 1000 = 0.12 mg
mass of C₁₂H₂₂O₁₁ (Sucrose) = 0.12 mg
