Answer:
2x-7+15=0
Step-by-step explanation:
we have, the eqn of st. line in two points form is
y-y1=y2-y1/x2-x1 (x-x1)
or, y-7=3-7/2-4 (x-(-4))
or, y-7=-4/-2 (x+4)
or, y-7=2 (x+4)
or, y-7=2x+8
or, 0=2x-y+8+7
or, 2x-y+15=0 is the required eqn
The equation of the line is "[tex]2x-y=1[/tex]"
Given points are:
The slope of the line will be:
→ [tex]m = \frac{y_2-y_1}{x_2-x_1}[/tex]
[tex]= \frac{3-7}{2-4}[/tex]
[tex]= \frac{-4}{-2}[/tex]
[tex]= 2[/tex]
hence,
The equation of the line will be:
→ [tex](y-y_1) = m(x-x_1)[/tex]
[tex]y - 7 = 2(x-4)[/tex]
[tex]y-7=2x-8[/tex]
[tex]y = 2x-8+7[/tex]
[tex]y=2x-1[/tex]
[tex]2x-y=1[/tex]
Thus the above answer is right.
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