AshuraTheGlitchHog
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A Roller Derby Exhibition recently came to town. They packed the gym for two
consecutive weekend nights at South's field house. On Saturday evening, the
68-kg Anna Mosity was moving at 17 m/s when she collided with 76-kg Sandra
Day O'Klobber who was moving forward at 12 m/s and directly in Anna's path.
Anna jumped onto Sandra's back and the two continued moving together at
the same speed. Determine their speed immediately after the collision.

Respuesta :

ohiekulous

Answer:

14.36m/s

Explanation:

From the law of conservation of linear momentum

m1u1 + m2u2 = v(m1 + m2)

68×17 + 76×12= v(68+76)

1156+912 = 144v

2068 = 144v

v = 2068/144

=14.36 m/s

kapoorprachi783

Their speed immediately after the collision is 14.36m/s.

The law of conservation of linear momentum

Conservation of linear momentum, the general law of physics according to which the quantity called momentum that characterizes motion never changes in an isolated collection of objects.

From the law of conservation of linear momentum, we get:

m1u1 + m2u2 = v(m1 + m2)

⇒ m1 = mass of particle and m2 = mass of particle

Given :

⇒ m1 = 68 kg

⇒ m2 = 76kg

⇒ u1 = 17 m/s

⇒ u2 = 12 m/s

By substituting the value in formula, we get:

⇒ 68×17 + 76×12= v(68+76)

⇒ 1156+912 = 144v

⇒ 2068 = 144v

⇒ v = 2068/144

⇒ 14.36 m/s

What is the law of conservation of linear momentum?

The law of conservation of linear momentum states that when no external forces act on a system of two colliding objects, the vector sum of their linear momentum remains constant and is unaffected by their mutual interaction.

Learn more about law of conservation here: brainly.com/question/166559

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