Answer:
0
Step-by-step explanation:
The average rate of change of the function H(t) over the interval [tex]-5\le t\le -1[/tex] can be calculated as
[tex]\dfrac{H(-1)-H(-5)}{(-1)-(-5)}[/tex]
Find H(-5) and H(-1):
[tex]H(-5)-(-5+3)^2+5=(-2)^2+5=4+5=9\\ \\H(-1)=(-1+3)^2+5=2^2+5=9[/tex]
Then
[tex]H(-1)-H(-5)=9-9=0[/tex]
and the average rate of change is 0.
