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The rectangle shown has a perimeter of 106 cm and the given area. It’s length is 8 more than four times the width. Write and solve a system of equations to find the dimensions of the rectangle

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laurellee27

Answer:

Step-by-step explanation:

p = 106

L = 8 + 4W

p = 2L + 2W

p = 2(8 + 4W) + 2W

p = 16 + 8W + 2 W

p = 16 + 10W

106 = 16 + 10W

106 - 16 = 10W

90 = 10W

90/10 = W

9 = W

W = 9

L = 8 + 4W

L = 8 + 4(9)

L = 8 + 36

L = 44

44 + 44 + 9 + 9 = 106

44 * 9 = Area = 396

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