PLEASE HELP

Complete and balance the following semi-reactions and indicate if it is oxidation or reduction:
TiO2 (s) → Ti2 + (aq) (acid medium)

Mn2 + (aq) → MnO2 (basic medium)

Respuesta :

For the first eqn:
Mn2+(aq) -> MnO2(s) [basic sln]
Step 1: Balance elements other than O and H. Mn is already balanced.
Mn2+(aq) -> MnO2(s)
Step 2: Add H2O to balance O.
2H2O(l) + Mn2+(aq) -> MnO2(s)
Step 3: Add H+ ions to balance out H.
2H2O(l) + Mn2+(aq) -> MnO2(s) + 4H+
Step 4: Add OH- as it is a basic solution. Must do it to both side to balance.
2H2O(l) + Mn2+(aq) + 4OH- -> MnO2(s) + 4H+ + 4OH-
Simplified to
2H2O(l) + Mn2+(aq) + 4OH- -> MnO2(s) + 4H2O(l)
Step 5: Balance the charges by adding electrons.
2H2O(l) + Mn2+(aq) + 4OH- -> MnO2(s) + 4H2O(l) + 2e-
Step 6: Check that all element and charges are balanced.
For the Second :
TiO2(s) → Ti2+(aq) [Acidic Sln]
Step 1) TiO2(s) -> Ti2+(aq)
Step 2) TiO2(s) -> Ti2+(aq) + 2H2O(l)
Step 3) TiO2(s) + 4H+ -> Ti2+(aq) + 2H2O(l)
Step 4) Omit as it is an acidic solution so you do not have to add OH- to neutralise the H+ ions.
Step 5) TiO2(s) + 4H+ + 2e- -> Ti2+(aq) + 2H2O(l)
Hope that helps you to see where you went wrong.
Note: I'm not sure whether you need to put states for H+ and OH- ions. But they would both be (aq).

Oxidation is the reaction in which atom or molecule lose its electrons. The titanium oxide is reducing while manganese is oxidizing in the reactions.

Reduction:

It is type of reaction in which atom or molecule gain electrons. For example,

[tex]\bold{TiO_2(s) +4H^+\rightarrow Ti^2^+ + 2H_2O}[/tex]

  • Titanium oxide gain electrons from Hydrogen ion to form titanium ion and water.

Oxidation:

It is a type of reaction in which an atom or a molecule loose its electrons. For example,

[tex]\bold{2Mn^2^+ + 2H_2O +4OH^- \rightarrow 2MnO_2 + 4H^+ +4OH^-}[/tex]

  • Manganese ion react with water and loose its electrons to form Magnesium oxide.
  • Since, medium is basic [tex]\bold{OH^-}[/tex] will neutralize all [tex]\bold{H^+}[/tex] ions

Therefore, the titanium oxide is reducing while manganese  is oxidized in the reactions.

To know more about Oxidation, refer to the link:

https://brainly.com/question/13182308