contestada

Set up an equation and solve the following problem.
Kent drives 230 miles in the same time that it takes Dave to drive 210 miles. If Kent averages 4 miles per hour faster than Dave, find their rates.
Dave mph
Kent mph

Respuesta :

Answer:

The speed of Dave is 42 miles per hour

The speed of Kent is 46 miles per hour .

Step-by-step explanation:

Given as :

The distance cover by Dave = d = 210 miles

The time taken by Dave = t hour

The speed of Dave = s miph

Again

The distance cover by Kent = D = 230 miles

The time taken by Kent = T hour

The speed of Kent = S = (s + 4 ) miph

For Dave

Time = [tex]\dfrac{\textrm Distance}{\textrm Speed}[/tex]

So, t = [tex]\dfrac{\textrm d miles}{\textrm s miph}[/tex]

Or, t = [tex]\dfrac{\textrm 210 miles}{\textrm s miph}[/tex]

For Kent

Time = [tex]\dfrac{\textrm Distance}{\textrm Speed}[/tex]

So, T = [tex]\dfrac{\textrm D miles}{\textrm S miph}[/tex]

Or, T = [tex]\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}[/tex]

∵ Time taken by both is same

So, t = T

Or,  [tex]\dfrac{\textrm 210 miles}{\textrm s miph}[/tex] = [tex]\dfrac{\textrm 230 miles}{\textrm (s + 4) miph}[/tex]

Or, 210 × (s + 4) = 230 × s

Or, 210 × s + 210 × 4 = 230 × s

Or, 210 × 4 = 230 × s -210 × s

Or, 210 × 4 = 20 × s

∴  s = [tex]\dfrac{840}{20}[/tex]

i.e s = 42 miph

So, The speed of Dave = s = 42 miles per hour

Again

The speed of Kent = S = (s + 4 ) miph

i.e S = 42 + 4

or, S = 46 miph

So, The speed of Kent = S = 46 miles per hour

Hence,The speed of Dave is 42 miles per hour

And The speed of Kent is 46 miles per hour . Answer

Otras preguntas