1) The work done is 1800 J
2) The work done is 1721 J
Explanation:
1)
The work done by a force when pushing an object is given by:
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this problem, we have:
F = 150 N is the force applied to the box
d = 12 m is the displacement
[tex]\theta = 0^{\circ}[/tex], since the force is applied horizontally and the box moves horizontally
Therefore, the work done is
[tex]W=(150)(12)(cos 0)=1800 J[/tex]
2)
Again, the work done is given by
[tex]W=Fd cos \theta[/tex]
where
F is the magnitude of the force
d is the displacement of the object
[tex]\theta[/tex] is the angle between the direction of the force and of the displacement
In this second problem, we have:
F = 150 N
d = 12 m
[tex]\theta=17^{\circ}[/tex], since this time the force is applied at a certain angle
Substituting, we find the work done in this case:
[tex]W=(150)(12)(cos 17^{\circ})=1721 J[/tex]
Learn more about work:
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