Solve the real-world situation by using the substitution method.
The length of a rectangular room is 7 feet more than its width. The perimeter of the room is 70 feet.
Let L represent the length of the room and W represent the width in centimeters.
L=W +7
The system of equations
70 = 2 + 2W cano
can be used to represent this situation.
What are the room's dimensions?

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absor201 absor201 · Answer 1 · 2020-01-18T14:37:40+01:00

The room has a length of 21 feet and width of 14 feet.

Step-by-step explanation:

Given,

Width of rectangular room = W

Length of rectangular room = W+7

Perimeter of room = 70 feet

L = W+7 Eqn 1

70 = 2L + 2W Eqn 2

Putting value of L from Eqn 1 in Eqn 2

[tex]70=2(W+7)+2W\\70=2W+14+2W\\70=4W+14\\70-14=4W\\56=4W\\4W=56[/tex]

Dividing both sides by 4

[tex]\frac{4W}{4}=\frac{56}{4}\\W=14[/tex]

Putting W=14 in Eqn 1

[tex]L=14+7\\L=21[/tex]

The room has a length of 21 feet and width of 14 feet.

Keywords: linear equation, substitution method

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