The probability for rolling a sum of 7 is: 1/6
Step-by-step explanation:
Given that two six-sided dies are rolled the total outcomes will be:
[tex]6*6 =36[/tex]
n(S) = 36
Out of total outcomes we have to count the outcomes that sum up to 7
Let A be the event that the sum of outcomes is 7
[tex]A = \{(1,6), (2,5), (3,4) , (4,3) , (5,2), (6,1)\}[/tex]
Here the first number is the result of first die and second number is the result of 2nd die.
n(A) = 6
So the probability of A will be:
[tex]P(A) = \frac{n(A)}{n(S)}\\\\=\frac{6}{36}\\\\=\frac{1}{6}[/tex]
Hence,
The probability for rolling a sum of 7 is: 1/6
Keywords: Probability, sample space
Learn more about probability at:
- brainly.com/question/1446555
- brainly.com/question/1446243
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