Given 24.3 g of LICI, Find moles of PbCI, produced.
PbSO4 + LiCl → PbCl2 + Li2SO4
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Answer:
0.29 moles of PbCl₂
Explanation:
Given data:
Mass of lithium chloride = 24.3 g
Moles of PbCl₂ = ?
Solution:
Chemical equation;
PbSO₄ + 2LiCl → PbCl₂ + Li₂SO₄
Number of moles of LiCl:
Number of moles = mass/ molar mass
Number of moles = 24.3 g/ 42.394 g/mol
Number of moles = 0.57 mol
Now we will compare the moles of PbCl₂ with LiCl .
LiCl : PbCl₂
2 : 1
0.57 : 1/2×0.57 = 0.29 mol