Answer:
[tex]\frac{\text{25,00 kg}}{\text{m}^3}[/tex]
Step-by-step explanation:
We have been given that a sheet of glass has a density of [tex]2.5\frac{\text{g}}{\text{cm}^3}[/tex]. We are asked to find the density of the glass in [tex]\frac{\text{kg}}{\text{cm}^3}[/tex].
We know that 1 meter equals so 100 cm.
[tex]\text{ 1 m}^3=(\text{ 100 cm})^3[/tex]
[tex]\text{ 1 m}^3=\text{ 1,000,000 cm}^3[/tex]
[tex]2.5\frac{\text{g}}{\text{cm}^3}\times \frac{\text{1,000,000 cm}^3}{\text{ 1 m}^3}}[/tex]
[tex]\frac{\text{2.5 g}}{\text{m}^3}\times 1,000,000[/tex]
[tex]\frac{\text{25,00,000 g}}{\text{m}^3}[/tex]
We also know that 1 kg equals 1000 grams.
[tex]\frac{\text{25,00,000 g}}{\text{m}^3}\times \frac{\text{1 kg}}{1,000\text{ gm}}[/tex]
[tex]\frac{\text{25,00 kg}}{\text{m}^3}[/tex]
Therefore, the density of the glass sheet is 2500 kg per cubic meter.
