The values of a, b, and c in given quadratic equation are:
a = 6 and b = -9 and c = 7
Solution:
Given quadratic equation is:
[tex]-6x^2 = -9x + 7[/tex]
Let us first convert the given quadratic equation to standard form
The standard form is [tex]ax^2+bx+c=0[/tex] with a, b, and c being constants, or numerical coefficients, and x is an unknown variable
[tex]-6x^2 = -9x + 7\\\\-6x^2+9x-7=0\\\\6x^2-9x+7=0[/tex]
Now we have to find the values of a, b, c
[tex]\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}[/tex]
Thus comparing [tex]6x^2-9x+7=0[/tex] with standard form of quadratic equation [tex]a x^{2}+b x+c=0[/tex]
a = 6
b = -9
c = 7
Thus values of a, b, and c are found
Answer:
a=-6 b=-9 c=7
i just took this test and i got it right
