Answer:
Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.
Explanation:
Hello,
In this case, the undergoing chemical reactions with their proper Gibbs free energy of reaction are:
[tex]A->B;\Delta _rG^o=-13 kJ/mol[/tex]
[tex]C ->D ;\Delta _rG^o=3.5 kJ/mol[/tex]
The cellular concentrations are as follows: [A] = 0.050 mM, [B] = 4.0 mM, [C] = 0.060 mM and [D] = 0.010 mM.
For each case, the reaction quotient is:
[tex]Q_1=\frac{4.0mM}{0.050mM}=80\\ Q_2=\frac{0.010mM}{0.060mM}=0.167[/tex]
A typical temperature at a cell is about 30°C, in such a way, the equilibrium constants are:
[tex]K_1=exp(-\frac{-13000J/mol}{8.314J/mol*K*303.15K} )=173.8\\K_2=exp(-\frac{3500J/mol}{8.314J/mol*K*303.15K} )=0.249[/tex]
Therefore, Q < K for both reactions. Both are spontaneous at those concentrations of substrate and product.
Best regards.
