Answer:
0.26 L
Explanation:
Data given
Volume of acetic acid (HC₂H₃O₂) (V1) = ?
Molarity of acetic acid (HC₂H₃O₂) (M1) = 17.4 mol/L
Volume of acetic acid (HC₂H₃O₂) (V2) = 4.5 L
Molarity of acetic acid (HC₂H₃O₂) (M2) = 1.0 mol/L
Solution:
As we diluting the concentrated acetic acid (HC₂H₃O₂)
So, Dilution formula will be used
M1V1 = M2V2
Put values in above equation
17.4 mol/L x V1 = 1.0 mol/L x 4.5 L
Rearrange the above equation
V1 = 1.0 mol/L x 4.5 L / 17.4 mol/L
V1 = 4.5 mol / 17.4 mol/L
V1 = 0.26 L
So 0.26 L of acetic acid (HC₂H₃O₂) is required
