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A light bulb connects to a battery. A second, identical light bulb connects in parallel to the first light bulb. The connecting wires have negligible resistance. When the switch is closed, the original light bulb will:
O no longer light.
O become brighter.
O become dimmer.
O experience no change in brightness.

Respuesta :

Answer:d

Explanation:

Suppose V is the voltage of battery and R is the resistance of bulb

so Power drop for initial stage

[tex]P_1=\frac{V^2}{R}[/tex]

When another identical bulb of same resistance is applied in parallel so voltage Drop across both the resistor will be same i.e. V

so Power consumed  [tex]P_2=\frac{V^2}{R}[/tex]

so there is no change in power and hence no dip in brightness  

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