David helped his father stick the pond with baby catfish and blue gill.They out in a total of 75 fish.If the number of blue gill was doubled and the number of catfish tripled,there would be 175 fish in the pond.How many catfish were put in the pond.

Respuesta :

Answer:

50 catfish were put in the pond.

Step-by-step explanation:

Given:

Total Number of fishes in the pond = 75

Let number of catfish be 'c'.

Also Let number of blue gill be 'b'

So We can say that;

Total Number of fishes in the pond  is equal to sum of number of catfish and number of blue gill.

framing in equation form we get;

[tex]c+b =75 \ \ \ \ equation \ 1[/tex]

Also Given:

If the number of blue gill was doubled and the number of catfish tripled,there would be 175 fish in the pond.

It means that;

2 multiplied by number of catfish plus 3 multiplied by number of blue gill is equal to 175.

framing in equation form we get;

[tex]2c+3b =175 \ \ \ \ equation \ 2[/tex]

Now Multiplying equation 1 by 2 we get;

[tex]2(c+b) =75\times2\\\\2c+2b =150 \ \ \ \ equation\ 3[/tex]

Now Subtracting equation 3 from equation 2 we get;

[tex](2c+3b)-(2c+2b)=175-150\\\\2c+3b-2c-2b=25\\\\b=25[/tex]

Now Substituting the Value of b in equation 1 we get;

[tex]c+b=75\\\\c+25=75\\\\c=75-25 =50[/tex]

Hence 50 catfish were put in the pond.