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What is the internal energy of 4.50 mol of N2 gas at 253°C? To solve this
problem, use the equation: Wciatomic gas == nRT
Remember that R = 8.31 J/(mol·K) and K = °C + 273.
O A. 94,600 J
O B. 23,700 J
O C. 9460
O D. 49,200 J

Respuesta :

skyluke89

The internal energy of the gas is 49,200 J

Explanation:

The internal energy of a diatomic gas, such as [tex]N_2[/tex], is given by

[tex]U=\frac{5}{2}nRT[/tex]

where

n is the number of moles

R is the gas constant

T is the absolute temperature of the gas

For the gas in this problem, we have:

n = 4.50 (number of moles)

R = 8.31 J/(mol·K) (gas constant)

[tex]T=253^{\circ} + 273 = 526 K[/tex] (absolute temperature)

Substituting, we find:

[tex]U=\frac{5}{2}(4.50)(8.31)(526)=49,200 J[/tex]

Learn more about ideal gases:

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