Answer:
(A) 1/2 kA2 and 1/2 mv2 (max)
Explanation:
As we know that
1)In the SHM at mean position velocity become maximum and at the extreme position velocity become zero.
2)In the SHM at the mean position acceleration become zero and the extreme position it become maximum.
The total energy at the extreme position given as
[tex]TE=\dfrac{1}{2}KA^2[/tex]
A =Amplitude
K=Spring constant
The total energy at the mean position given as
[tex]TE=\dfrac{1}{2}mV^2[/tex]
m=mass
V==Velocity
Therefore the answer will be A.
