The minimum work needed is 1456.4 J for 1 meter of ramp
Explanation:
There is one force pushing the car down along the slope: the component of the weight parallel to the slope, which is given by
[tex]W_p = mg sin \theta[/tex]
where
m = 950 kg is the mass of the car
[tex]g=9.8 m/s^2[/tex] is the acceleration of gravity
[tex]\theta=9.0^{\circ}[/tex] is the angle of the ramp
Therefore, the minimum force needed to push the car up along the ramp must be equal to this force:
[tex]F=W_p = mg sin \theta = (950)(9.8)(sin 9.0^{\circ})=1456.4 N[/tex]
The minimum work done to push the car along the ramp is therefore:
[tex]W=Fd[/tex]
where d is the length of the ramp. In this problem, it is not specified, so I assume it is
d = 1 m
And therefore, the minimum work required is:
[tex]W=Fd=(1456.4)(1)=1456.4 J[/tex]
Learn more about work:
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