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Bad gums may mean a bad heart. Researchers discovered that 81% of people who have suffered a heart attack has periodontal disease, an inflammation of the gums. Only 30% of healthy people have this disease. Suppose that in a certain community heart attacks are quite rare, occurring with only 15% probability.

If someone has periodontal disease, what is the probability that he or she will have a heart attack?

Respuesta :

Answer:

0.405 or 40.5%

Step-by-step explanation:

Let event A=having a periodontal disease

event B=having a heart attack

we are given

P(A)=P(having a periodontal disease)=0.30

P(B)=P(having a heart attack)=0.15

P(A/B)=P(have a periodontal disease/have a heart attack)=0.81

P(B/A)=P(have a heart attack/have a periodontal disease)=?

P(A/B)=P(A∩B)/P(B)

P(A∩B)=P(B)*P(A/B)=0.15*0.81=0.1215

P(B/A)=P(A∩B)/P(A)=0.1215/0.3=0.405

There is 40.5% probability that if someone has periodontal disease will have a heart attack.

francocanacari

The probability that he or she will have a heart attack is 40.5%.

Given that researchers discovered that 81% of people who have suffered a heart attack had periodontal disease, while only 30% of healthy people have this disease, supposing that in a certain community heart attacks are quite rare, occurring with only 15% probability, to determine, if someone has periodontal disease, what is the probability that he or she will have a heart attack, the following calculation must be performed:

 

  • 30 = 81
  • 15 = X
  • 1215/30 = X
  • 40.5 = X

Therefore, the probability that he or she will have a heart attack is 40.5%.

Learn more about probability in https://brainly.com/question/25720844

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